I have a small, hobby machine shop with a bunch of woodworking and
metalworking equipment. Some of it runs on 120v AC, some on 240v
AC, and some on 240v 3-phase AC. On the border of my farm runs a
high voltage 3-phase distribution line, so it looks like it would be
easy for me to get 3-phase to the building, but I was quoted about
$12,000 to install a couple of poles, a transformer, and connect to
my barn. So I started thinking about rotary 3-phase convertors.
My brother Joe got me a great deal on a big, 25 hp, 20 kVA 3-phase motor.
And I started reading about convertor circuits.
Here's the best example I found from a great online forum PracticalMachinist.com.
I ended up with this circuit.
The 25hp idler motor (which incidentally is waaaay oversized for my application) is driven
by single phase 240v connected directly to two legs of the motor.
Then there are 4 capacitors: Run capacitors Cp and Cs, Start capacitor Cstart, and Power Factor correction capacitor Cpf.
Cstart is connected only momentarily to start the 3-phase idler
motor turning. If you turn it on without pushing the start button,
it just humms for about 3 seconds before blowing the 50amp breaker.
And, if you leave Cstart connected for more than about half a
second, the lights go down in the shop ;-). So the starting process
is close the start switch, then one-two, close the main switch and
open the start switch. The big Cstart drives motor leg C with
current that leads the L1 voltage by 90°.
The spinning motor then generates voltage at terminal C. But this voltage is a little weak,
so we add Cp and Cs to help it be stronger. There's a bit of an art to tuning these capacitor values.
It goes like this, all while the motor is idling with no loads connected:
Measure Vab to get your nominal RMS AC voltage, say it's 240v.
Measure Vac and you'll find it is a bit low, like 210v. So
add capacitance to Cp until Vac comes up to about 8% larger than
Vab or about 260v.
Now measure Vbc and add capacitance to Cs until Vbc comes up to about 3% over Vab or 247v.
There, you are done with the big run capacitors.
Last step is to add capacitance to Cpf to minimize the input current measured at L1 or L2.
This power factor correction capacitor compensates for the inductive load of a motor and keeps things a bit cooler.
So what does the output look like?
I measured the RMS volts at T1, T2, and T3 relative to ground with a
Fluke multimeter. It doesn't look like 3-phase 240v does it? I see
118.8, 117.5, and 212.6 volts. The two 118 volt legs make sense.
They are the input phases L1 and L2 and between them is 240v. And
L3 is close to 240 volts, but that's not what I expected. I thought
I'd see something that looks like 3 equal phases, each something
like cos(60°) * 240 or 208v from ground. But a circuit like this
cannot do that. A and B are connected directly to L1 and L2. They
can't suddenly be a lower voltage or a different phase. Not unless
the supply leeds from the power company are very long and have
significant inductance. And in this case they don't. The power
company supply is "very stiff".
But when I measure the phase-to-phase voltages on the 3-phase outputs
T1-T2, T1-T3, and T2-T3, the voltages are well behaved, all near 240v.
I got 237, 245, and 242 volts. All good, right?
No, the problem is this is not 120° 3-phase 208. It's 90°
3-phase 240. Fine, 3-phase motors are happy enough with this that
all the machines run just fine. My 3 hp Accra knee mill is fine, my
5 hp Grob bandsaw is fine, my 1 hp Boyer Schultz surface grinder is
fine, my 1 hp Baldor pedastal grinder is fine, and my 7.5 hp monster
dual 30" disc sander is fine (acutally I haven't powered that last
one up yet, but I'm sure it will OK too).
Here's a little experiment I ran while watching the phase-to-ground voltages with an oscilloscope.
You clearly see the 90° relationship while the system is powered up, but the moment I open the
input switch, the phases snap to 120° as the three motors coast down.
Three phase motors are wound with equally spaced windings that work
best with 120° separated power phases. When they are supplied
with 90° phases, the motor pole pieces don't line up right and
the motor performance is slightly degraded. What this means in
practice is that if I was doing a maximum-performance cut for an
extended period of time, the motor would overheat. Or more
practically, the motors will all run a bit warmer than they would if
I had perfect, utility-supplied, 3-phase power. For these machines,
I'll never notice the difference.
There's another consideration, and that is mixed phase equipment.
For example, the Boyer-Schultz surface grinder has a magnetic chuck
which runs off a nominal 120v AC supply. It is wired to use one of
the 3-phase input phases to power the chuck and returns that current
to ground. If I connect the chuck supply to L1 or L2 (A or B) but
not C it will work perfectly. But if I were to use C, it would be
getting 212 volts. Not a nice thing to do to a 120 volt device. So
watch out when connecting things like 120v work lights, or DRO, or
the X-axis power-feed on the mill.
This is bugging me, so I got to thinking... you know how that goes....
How can I get the input phases to not be separated by 180°? If
the power lines had some inductance, the voltage could be pulled off
of 180° What if I add some inductance, or better yet the right
ratio of inductance and capacitance to pull the phase back 60°?
Then maybe the motor would start easily, maybe even without a start
capacitor bank and a start switch. And the three phases would be
much closer to 120° separated.
I've forgotten most of the EE math I did freshman or sophomore year
about 40 years ago. You know, that Laplace trasnform stuff with the
s-variable and reactive impedances like s×C. But I do know how to
write differential equations and solve them with numerical integration.